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Tangency and number of solutions of transcendental equations

mathematical
Consider the equation ln⁡x=kx\ln x = kx, where kk is a real constant.
The curve y = ln x with lines y = kx through the origin: the tangent line k = 1/e touching at (e, 1), a line with 0 < k < 1/e crossing twice, and a line with k < 0 crossing once.
Facts you may need
  • Tangent touches with equal value and equal gradient — $\ln a = ka$ and $\frac1a = k$.
  • ln⁡x\ln x is increasing and concave — Shapes the number of crossings.

(a)

Find the value of kk for which the line y=kxy = kx is a tangent to y=ln⁡xy = \ln x, and the point of contact.

(b)

State, with reasons, the number of solutions of ln⁡x=kx\ln x = kx for all real kk.