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Electron Echoes from a Crystal Surface

de Broglie and wave–particle duality

A materials scientist at a Wellington laboratory studies the surface of a new alloy using low-energy electron diffraction. Electrons are accelerated from rest through a potential difference VV and strike the crystal surface at normal incidence. The surface atoms are arranged in parallel rows a distance dd apart, and they act like a reflection grating: back-scattered electrons produce strong maxima at angles θ\theta from the normal given by dsin⁡θ=nλd\sin\theta = n\lambda, where nn is the order. The electron speeds are non-relativistic. The scientist measures the angle θ1\theta_1 of the first-order maximum at several accelerating voltages: V (V)V\ (\text{V}): 50.0, 80.0, 120, 180, 250 θ1 (∘)\theta_1\ (^\circ): 44.3, 33.1, 26.6, 21.7, 17.9
Data: h = 6.63 × 10⁻³⁴ J s · c = 3.00 × 10⁸ m s⁻¹ · e = 1.60 × 10⁻¹⁹ C · mₑ = 9.11 × 10⁻³¹ kg

(a)

show that2 marks
Show that the de Broglie wavelength of the electrons is λ=h2meeV\lambda = \dfrac{h}{\sqrt{2m_e eV}}, and calculate it for V=120 VV = 120\ \text{V}.

(b)

explain2 marks
Explain why the de Broglie relation predicts that a graph of sin⁡θ1\sin\theta_1 against 1/V1/\sqrt{V} is a straight line through the origin, and state what its gradient represents. Use the data to find the gradient, and hence determine the row spacing dd. Comment on whether the data support the de Broglie relation.

(c)

derive2 marks
Taking d=0.250 nmd = 0.250\ \text{nm}, the scientist gradually lowers the accelerating voltage. Explain what happens to the positions of the maxima, and derive an expression for the voltage V2V_2 below which the second-order maximum can no longer be observed. Evaluate it.

(d)

compare2 marks
A colleague suggests using photons with the same energy as the electrons (120 eV) instead. Show that the ratio of photon wavelength to electron wavelength for the same energy EE is 2mec2E\sqrt{\dfrac{2m_ec^2}{E}}, evaluate it, and discuss whether 120 eV photons could be used to observe this diffraction pattern. What photon energy would be needed to give the same wavelength as the electrons?

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