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Methanol as a liquid carrier for hydrogen

ΔH by two methods, entropy and temperature, Kc and Q, fuels and intermolecular forces

Methanol can be made from synthesis gas: CO(g)+2 HX2(g)⇌CHX3OH(g)\ce{CO(g) + 2H2(g) <=> CH3OH(g)}, using a Cu/ZnO catalyst at about 250 °C and 50–100 atm. ΔfH\Delta_fH (kJ mol−1^{-1}): CO(g) −111; CHX3OH(g)\ce{CH3OH(g)} −201. Bond enthalpies (kJ mol−1^{-1}): C≡O (in CO) 1077; H–H 436; C–H 414; C–O 358; O–H 463. ΔcH\Delta_cH (kJ mol−1^{-1}): CHX3OH(l)\ce{CH3OH(l)} −726; HX2(g)\ce{H2(g)} −286. M (g mol−1^{-1}): CHX3OH\ce{CH3OH} 32.0; HX2\ce{H2} 2.0.
Facts you may need
  • ΔfH and bond enthalpy methods
  • entropy of gases
  • Kc and Q
  • intermolecular forces and state

(a)

Calculate ΔrH\Delta_rH using (i) ΔfH\Delta_fH data and (ii) bond enthalpies. Explain why the values differ.

(b)

Predict the sign of ΔS\Delta S for the system and explain why the reaction becomes less favourable at high temperature.

(c)

1.00 mol CO and 2.00 mol HX2\ce{H2} are sealed in a 2.00 L vessel at the operating temperature. At equilibrium, 0.300 mol of CHX3OH\ce{CH3OH} is present. Calculate KcK_c.

(d)

Justify the industrial choice of 250 °C, 50–100 atm and a Cu/ZnO catalyst. First, for a mixture at the same temperature with [CO]=0.20[\ce{CO}] = 0.20, [HX2]=0.50[\ce{H2}] = 0.50 and [CHX3OH]=0.30[\ce{CH3OH}] = 0.30 mol L−1^{-1}, determine the direction of net reaction.

(e)

Compare the energy released per kilogram by burning methanol and hydrogen. Despite its lower value, methanol is proposed as a way to store and transport hydrogen. Explain, with reference to particles and forces, why methanol is easier to store.